Answer:
The proportion of 1s received at the end of the channel is of 0.598.
Explanation:
In this question:
60% of the bits sent are 1, 100 - 60 = 40% of the bits sent are 0.
For each bit receive, 0.01 probability of an error, so 0.99 probability it is correct.
a. What is the proportion of 1s received at the end of the channel?
99% of 60%(sent 1s, received 1).
1% of 40%(sent 0s, received 1). So
The proportion of 1s received at the end of the channel is of 0.598.