Question

A 70.7 kg high jumper leaves the ground with

a vertical velocity of 6.7 m/s.
How high can he jump? The acceleration
of gravity is 9.8 m/s^2.
Answer in units of m

Answer 1

Hi there!

We can use the following kinematic equation:

`v_f^2 = v_i^2 + 2ad`

vi = initial velocity (6.7 m/s)
vf = final velocity (0 m/s at top of trajectory)

a = acceleration due to gravity (-9.8 m/s²)

d = max height reached (? m)

We can plug in the knowns:

`0 = 6.7^2 + 2(-9.8)(d)\\\\`

Solve for 'd':

`d = (6.7^2)/(2(9.8)) = \boxed{2.29 m}`