Answer:
a) 0.99999 e
b) 1*10^-5 s
c) 3*10^-2 m
Step-by-step explanation:
Given data:
Electron energy : 50 GeV
assuming the rest mass of an electron = 0.5 MeV/c^2
A) Determine the velocity of each electron
velocity of each electron ( v ) ≈ 0.999 e
B) How much time does it take the electrons to travel the length of the accelerator given that the accelerator = 3km long
Lo = 3 * 10^3 m
T = (3 * 10^3 )/ (0.999 * 3 * 10^8)
= 1 * 10 ^-5
C) How long does the accelerator look form the perspective of the electrons
L = Lo / r = Lo
hence L = 3 * 10^-2 m