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Which of the following is a valid unit of power?

Kg.m2/s
Kg.m2/ s3
J
Kg2.m2/ s3

User Nate Reed
by
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1 Answer

3 votes

Answer:

kg•m^2/s^3

Step-by-step explanation:

Here, we want to get the valid unit for power

Mathematically, power is time rate of doing work

Work is the product of force and distance

Unit for force is;

kg•ms^-2

work is;

Kg•ms^-2 • s

= kg•m^2•s^-2

Divide through by the s for time;

we have ;

kg•m^2•s^-2/s

kg•m^2•s^-3

And that is;

kg•m^2/s^3

User Yeray Diaz
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5.9k points