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A player kicks a football from ground level with an initial velocity of 27.0 30.0 above the horizontal Find the ball's maximum height

User Will Buck
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1 Answer

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Answer:

Given

initial velocity (u) =27.030

Force of gravidity g) =9.8

Rtc maximum height Hmix =?


sln \\ \ hmix = u {}^(2) / 2g \\ 27.030 / 2 * 9 \\ \\ hmix = 38.025m

User Elibud
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