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ax^2+bx+c=0 proof


User Wwwuser
by
8.7k points

1 Answer

9 votes

Answer

a= −bx−c / x2

Explanation:

ax2+bx+c=0

Step 1: Add -bx to both sides.

ax2+bx+c+−bx=0+−bx

ax2+c=−bx

Step 2: Add -c to both sides.

ax2+c+−c=−bx+−c

ax2=−bx−c

Step 3: Divide both sides by x^2.

ax2

x2

=

−bx−c

x2

a=

−bx−c

x2

User Roxanna
by
8.3k points

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