Question

Two lightbulbs work on a 120-V circuit One 50 W and the other is 100 W. Which bulb has a higher resistance? Explain pls!!!!

Answer 1

Bulb 1 has more resistance.

Step-by-step explanation:

Given that,

Two lightbulbs work on a 120-V circuit.

The power of circuit 1, P₁ = 50 W

The power of circuit 2, P₂ = 100 W

We need to find the bulb that has a higher resistance.

The power of the bulb is given by :

`P = (V^2)/(R)`

For bulb 1,

`R_1=(V^2)/(P_1)\\\\R_1=((120)^2)/(50)\\\\R_1=288\ \Omega`

For bulb 2,

`R_2=(V^2)/(P_2)\\\\R_2=((120)^2)/(100)\\\\R_2=144\ \Omega`

So, bulb 1 has higher resistance.