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38 votes
38 votes
Two 0.20-kg balls, moving at 4 m/s east, strike a wall. Ball A bounces backwards at the same speed. Ball B stops. Which statement correctly describes the change in momentum of the two balls?

a. |ΔpBl<|ΔPA|
b. |ΔpBl=|ΔPA|
c. |ΔpB|>|ΔPA|
d. ΔpB > ΔPA

User Arthurfnsc
by
2.7k points

1 Answer

9 votes
9 votes

Answer:

Option A

Step-by-step explanation:

From the question we are told that:

Mass
m=0.20kg

Velocity
v=4m/s

Generally the equation for momentum for Ball A is mathematically given by

Initial Momentum


M_(a1)=mV


M_(a1)=0.2*4


M_(a1)=0.8

Final Momentum


M_(a2)=-0.8kgm/s

Therefore


\triangle M_a=-1.6kgm/s

Generally the equation for momentum for Ball B is mathematically given by

Initial Momentum


M_(b1)=mV


M_(b1)=0.2*4


M_(b1)=0.8

Final Momentum


M_(b2)=-0 kgm/s

Therefore


|\triangle M_a|>|\triangle Mb|

Option A

User Vonlanthen
by
3.1k points