Question

Estimate the average power of a water wave when it hits the chest of an adult standing in the water at the seashore. Assume that the amplitude of the wave is 0.56 m , the wavelength is 2.0 m , and the period is 3.4 s . Assume that the area of the chest is 0.14 m^2.

Answer 1

`P=45.2W`

Step-by-step explanation:

From the question we are told that:

Amplitude
`A=0.56m`

Period
`T=3.4s`

Wavelength
`\lambda=2.0`

Area
`a=0.14m^2`

Generally the equation for Power is mathematically given by

`Power = 2 \pi ^2 \rho a((\lambda)/(T))((1)/(T))*A`

`P= 2 3.142^2 1025 0.14((2.0)/(3.4))((1)/(3.4))^2*0.56^2`

`P=45.2W`