Answer:
0.30625 Ci
Step-by-step explanation:
From the question given above, the following data were obtained:
Half-life (t½) = 5.73E3 years
Original activity (Nₒ) = 0.350 Ci
Time (t) = 1.719E4 years
Difference in activities =?
Next, we shall determine number of half-lives that has elapse. This can be obtained as follow:
Half-life (t½) = 5.73E3 years = 5.73×10³ years
Time (t) = 1.719E4 years = 1.719×10⁴ years
Number of half-lives (n) =?
n = t / t(½)
n = 1.719×10⁴ / 5.73×10³
n = 3
Thus, 3 half-lives has elapsed.
Next, we shall determine the activity after 1.719E4 years. This can be obtained as follow:
Original activity (Nₒ) = 0.350 Ci
Number of half-lives (n) = 3
Activity remaining (N) =?
N = 1/2ⁿ × Nₒ
N = 1/2³ × 0.350
N = 1/8 × 0.350
N = 0.125 × 0.350
N = 0.04375 Ci
Finally, we shall determine the difference in activities. This can be obtained as follow:
Original activity (Nₒ) = 0.350 Ci
Activity remaining (N) = 0.04375 Ci
Difference in activities =?
Difference in activities = Nₒ – N
Difference in activities = 0.350 – 0.04375
Difference in activities = 0.30625 Ci.