Answer: Attached below is the missing diagram
answer :
A) 1) Wr > WI, 2) Qc' > Qc
B) 1) QH' > QH, 2) Qc' > Qc
Step-by-step explanation:
л = w / QH = 1 - Qc / QH and QH = w + Qc
A) each cycle receives same amount of energy by heat transfer
( Given that ; Л1 = 1/3 ЛR )
1) develops greater bet work
WR develops greater work ( i.e. Wr > WI )
2) discharges greater energy by heat transfer
Qc' > Qc
solution attached below
B) If Each cycle develops the same net work
1) Receives greater net energy by heat transfer from hot reservoir
QH' > QH ( solution is attached below )
2) discharges greater energy by heat transfer to the cold reservoir
Qc' > Qc
solution attached below