Answer:
![\sf x=28^(\circ)](https://img.qammunity.org/2022/formulas/mathematics/high-school/v5bkczkvz541ftrv725ya6bq99agt9k10t.png)
Explanation:
The diagram given shows that ∠AOB and ∠BOC are complementary angles.
(When 2 angles measure adds up to 90° they are called complementary angles and when they add up to 180° they are called supplementary angles.)
![(\sf Complementary\: angles)](https://img.qammunity.org/2022/formulas/mathematics/high-school/rbdq3lkx6qg98mfunkc5gkpdq7c9pz9vda.png)
![\sf \angle AOB + \angle BOC=90^(\circ)](https://img.qammunity.org/2022/formulas/mathematics/high-school/6m7jq6ssupw6es81cfg51m2o3e8098gc19.png)
![\sf 62^(\circ)+x=90^(\circ)](https://img.qammunity.org/2022/formulas/mathematics/high-school/e4bd2duy903v4ixajp53w4r6fcinjnr8n8.png)
Subtract 62 from both sides:
![\sf 62^(\circ)+x-62^(\circ)=90^(\circ)-62^(\circ)](https://img.qammunity.org/2022/formulas/mathematics/high-school/mgyaciscgdad02d749j2cjjbiuk3f6x4w1.png)
![\sf x=28^(\circ)](https://img.qammunity.org/2022/formulas/mathematics/high-school/v5bkczkvz541ftrv725ya6bq99agt9k10t.png)
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