Question

In this diagram, ABAC – AEDF. If the

area of ABAC = 8 in2, what is the
area of AEDF?
D
E
3 in
F
B.
4 in
С
Area = [?] in?
Enter a decimal rounded to the tenths.

Answer 1

Area = 4.5 in.²

Explanation:

Area of ∆BAC = 8 in.²

EF = 3 in.

BC = 4 in.

Since both triangles are similar, therefore,

Area of ∆BAC : Area of ∆EDF = BC² : EF²

Plug in the values into the equation

8/area of ∆EDF = 4²/3²

Area of ∆EDF = (8*3²)/4²

= 4.5 in²