Register
What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°C to 70.0°C when 2,520 J of heat is applied? Use q equals m C subscript p Delta T..
223k views
20 votes
What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°C to 70.0°C when 2,520 J of heat is applied?

Use q equals m C subscript p Delta T..

User Betoharres
by
4.6k points

2 Answers

10 votes

Answer:

a

Step-by-step explanation:

User Stephen Himes
by
4.4k points
3 votes
Plug in what you know
-Heat (q) is 2520
-Delta T (change in temperature) is 70-10 which is 60
-Mass (M) is 10kg
-specific heat (c) is unknown.

2520 = (10)C(60)
Use algebra to solve for C.
Multiply C by 60 and 10.
2520 = 600C
Divide both sides by 600 to get C by itself.
C = 4.2 J/g
User Mhttk
by
3.7k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.5m questions

5.9m answers

Other Questions

What is the variable for this number 22.4L?
Which of the following aqueous solutions are good buffer systems? . 0.29 M perchloric acid + 0.15 M potassium perchlorate 0.16 M potassium acetate + 0.26 M acetic acid 0.18 M hydrofluoric acid + 0.12 M
Suppose a flask is filled with of , of and of . The following reaction becomes possible: The equilibrium constant for this reaction is at the temperature of the flask. Calculate the equilibrium molarity
1. If temperature is increased, the number of collisions per second do what
A helium balloon containing 0.100 mol of gas occupies a volume of 2.4 L at 25 C and 1.0 atm. how many moles have we added if we inflate it to 5.6 L?
Link Copied!