Question

A bowling ball is pushed with a force of 22.0 N and accelerates at 5.5 m/s2. What is the mass of the bowling ball?

Answer 1

4 kg

Step-by-step explanation:

F (force) = 22.0 N

m (mass) = ? (in Kg)

a (acceleration) = 5.5 m/s²

We apply the data to the Resultant Force formula, we have:

f=ma

22=m x 5.5

5.5m=22

m=22/5.5

m=4kg

Answer 2

`\boxed {\boxed {\sf 4 \ kilograms}}`

Step-by-step explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

`F= m*a`

The bowling ball was pushed with a force of 22.0 Newtons and the acceleration was 5.5 meters per second squared.

1 Newton is equal to 1 kilogram meter per second squared. Therefore, the force of 22.0 N is equal to 22 kg*m/s² (we do this conversion so we can easily cancel the units later).

• F= 22.0 kg*m/s²
• a= 5.5 m/s²

Substitute the values into the formula.

`22.0 \ kg*m/s^2 = m * 5.5 \ m/s^2`

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 5.5 meters per second squared. The inverse of multiplication is division, so we divide both sides by 5.5 m/s²

`\frac { 22.0 \ kg*m/s^2}{5.5 \ m/s^2} = (m * 5.5 \ m/s^2)/(5.5 \ m/s^2)`

`\frac { 22.0 \ kg*m/s^2}{5.5 \ m/s^2}=m`

The units of meters per second squared (m/s²) cancel.

`\frac { 22.0 \ kg}{5.5 }=m`

`4 \ kg =m`

The mass of the bowling ball is 4 kilograms.