Question

HELP ME PLEASE!!!!!!!!!!!​

Answer 1

9.y=Mx+b

Y= 2/5x+4

10. y=Mx+b

Y=4x-5

Explanation:

Answer 2

9)
`y=(2)/(5) x+4`

10)
`y=4x-5`

Explanation:

Slope-intercept form is
`y=mx+b` where
`m` is the slope and
`b` is the y-intercept, or the value of y when the line crosses the y-axis.

Question 9

`y=mx+b`

The question tells us that the slope of the line is
`(2)/(5)`. Because the slope is
`m`, plug
`(2)/(5)` into the equation as
`m`.

`y=(2)/(5) x+b`

Then, it tells us that the y-intercept is (0,4). Recall that the y-intercept is the value of y when the line crosses the y-axis. The value of y in the point (0,4) is 4. Because the y-intercept is
`b`, plug 4 into the equation as
`b`.

`y=(2)/(5) x+4`

Question 10

`y=mx+b`

First, we must calculate the slope using the slope equation:

`(y_2-y_1)/(x_2-x_1)` when the given points are
`(x_1,y_1)` and
`(x_2,y_2)`

The given points are (0,-5) and (2,3). Plug those into the equation.

`(3-(-5))/(2-0)`

Two negatives make a positive

`= (3+5)/(2-0)\\= (8)/(2) \\= 4`

Therefore, the slope of the line is 4. Plug 4 into the original equation as
`m`.

`y=4x+b`

Now, we can find the y-intercept by simply looking at the graph. The line crosses the y-axis at the point (0,-5). Therefore, the y-intercept is -5. Plug -5 into the equation as
`b`.

`y=4x+(-5)\\y=4x-5`

I hope this helps!