Question

Alice and Dave left school at the same time walking in opposite directions. Alice walked at an average speed of 280 ft/min and Dave walked at an average speed of 320 ft/min. How far apart were they in 10 minutes?

Answer 1

they were 600ft apart after 1 minute.

Explanation:

Distance = speed × time

Alice and Dave left school at the same time walking in opposite directions.

Alice walked at an average speed of 280 ft/min. It means that the distance covered by Alice in 1 minute is

280 × 1 = 280 ft

Dave walked at an average speed of 320 ft/min. It means that the distance covered by Dave in 1 minute is

320 × 1 = 320 ft

Total distance covered by both Alice and Dave in 1 minute is

280 + 320 = 600 ft

Answer 2

6000 ft

Explanation:

they walked apart at a rate of 600 ft /min because e320+280 so 600 x 10