Answer:
Explanation:
From the given information:
We can see that:
From equation (1), if we multiply it by 2, we will get what we have in equation (2).
It implies that,
x + 2y + 3z = 0 ⇔ 2x + 4y + 6z = 0
And, W satisfies the equation x + 2y + 3z = 0
i.e.
W = {(x,y,z) ∈ R³║x+2y+3z = 0}
Now, to determine the distance through the plane W and point is;
Here, the normal vector
is related to the plane x + 2y + 3z = 0
Suppose θ is the angle between the plane W and the point
, then the distance is can be expressed as: