Question

Find the zeros of the function.

9x^2-36=0
I've gotten half way right up to
9(x^2-4)=0​

Answer 1

x = ±2

Explanation:

9x^2-36=0

Using the square root property

9x^2 = 36

Divide each side by 9

x^2 = 4

Take the square root of each side

sqrt(x^2) = sqrt(4)

x = ±2