Question

If a bowling ball of mass 7.0 kg has a potential energy of 1100 Joules, how high above the ground is the bowling ball?

Answer 1

16.03m(2dp)

Step-by-step explanation:

Ep=m x g x h

1100=7.0x 9.8( gravitational field strength) x h

Height= 1100/7.0 x 9.8

=16.03498542

= 16.03m (2dp)