Question

A bag of candy has 21 orange, 18 red, and 10 yellow candies. What is the probability that an orange will be drawn first and then a red (without replacement)?

Answer 1

Total candies

• 21+18+10
• 49

After 1 replacement

• 49-1=48

So

P(candy,red)

• 21/49×18/48
• 9/56

Answer 2

• 9/56

Explanation:

There are:

• 21 orange candies
• 18 red candies
• 10 yellow candies

Total number:

• 21 + 18 + 10 = 49

Required probability is:

• P(o, r) = 21/49*18/48 = 9/56