Answer:
public void removePrefixStrings(List<String> list , String prefix) {
if(list==null || list.size()==0)
return;
for(int i=0; i<list.size();) {
if(list.get(i).startsWith(prefix))
list.remove(i);
else
++i;
}
}
Time Complexity: If the prefix is the same as String length, Then finding all prefix match will take n *n = n2
Then removal is also n
So the total time complexity is O(n3)