Question

2NO + 3MnO2 + 4H â 2NO3- + 3Mn2 + 2H2O For the above redox reaction, assign oxidation numbers and use them to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.

Answer 1

Manganese decreases from 4+ to 2+ (reduced and oxidizing agent) and nitrogen increases from 2+ to 5+ (oxidized and reducing agent).

Step-by-step explanation:

Hello there!

In this case, according to the given redox reaction, we rewrite it as a convenient first step:

`2NO + 3MnO_2 + 4H^+ \rightarrow 2NO_3^- + 3Mn^(2+) + 2H_2O`

Next, we assign the oxidation numbers as follows:

`2N^(2+)O^(2-) + 3Mn^(4+)O^(-2)_2 + 4H^+ \rightarrow 2(N^(5+)O^(2-)_3)^- + 3Mn^(2+) + 2H^+_2O^(2-)`

Thus, we can see that both manganese and nitrogen undergo a change in their oxidation number, the former decreases from 4+ to 2+ (reduced and oxidizing agent) and the latter increases from 2+ to 5+ (oxidized and reducing agent).

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