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Please help me with this its really needed

Please help me with this its really needed-example-1
User Puyol
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1 Answer

27 votes
27 votes

Answer:

f(x) = log x - 1 --> (10, 0)

f(x) = -(log x - 2) --> (100, 0)

f(x) = log(- x - 2) --> (-3, 0)

f(x) = -log-(x-1) --> (0, 0)

Explanation:

An x-intercept is the position where the value of y(in this case f(x)) is 0.

Let's start with the first equation:

f(x) = log x - 1

If f(x) is 0, we would get this equation:

0 = log x - 1

Now, we solve for x:

1 = log x

x = 10

This means the x-intercept is (10, 0).

f(x) = -(log x - 2)

Again, we can set f(x) to 0, and solve for x:

0 = -(log x - 2)

0 = log x - 2

2 = log x

x = 100

This means the x-intercept is (100, 0)

Same process applies for the third:

f(x) = log(- x - 2)

0 = log(- x - 2)

1 = -x - 2

3 = -x

x = -3

(-3, 0)

f(x) = -log-(x-1)

0 = -log-(x-1)

0 = log-(x-1)

1 = -(x-1)

1 = -x + 1

0 = -x

x = 0

(0, 0)

User Beactive
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