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Find unknown sizes of angles

Find unknown sizes of angles-example-1

2 Answers

14 votes

Answer:

x=a

(being alternate angles)

x+2a=110°

(Being sum of interior angles opposite to exterior angles)

or, a +2a =110°

or, 3a=110°

or, a=110°/3

therefore, a=36.67

Now;

2a = 2×36.67

= 73.34

the answer I solved is wrong please don't write it

User Dimentica
by
9.0k points
8 votes

Answer:

2a+110=180(co interior angle)

2a=180-110

a=70/2=35

2a=2×35=70

a=x=35 alternate angle

x+2a=y exterior angle of triangle is equal to the sum of two interior angle

35+70=y

y=105

User Basavaraj Hadimani
by
8.7k points

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