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16 votes
three consecutive odd integers are such that three times the smallest is 9 more than twice the largest find the three numbers​

1 Answer

4 votes

Answer:

17, 19, 21

Explanation:

let the 3 consecutive odd numbers be n, n + 2 and n + 4 , then

3n = 2(n + 4) + 9 ( 3 times smallest is 9 more than twice the largest )

3n = 2n + 8 + 9

3n = 2n + 17 ( subtract 2n from both sides )

n = 17

n + 2 = 17 + 2 = 19

n + 4 = 17 + 4 = 21

The 3 numbers are 17, 19, 21

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