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Below are \triangle ABC△ and \triangle DEF△DEFtriangle, D, E, F. We assume that AB=DEAB=DEA, B, equals, D, E, BC=EFBC=EFB, C, equals, E, F, and AC=DFAC=DFA, C, equals, D, F.

Below are \triangle ABC△ and \triangle DEF△DEFtriangle, D, E, F. We assume that AB-example-1
Below are \triangle ABC△ and \triangle DEF△DEFtriangle, D, E, F. We assume that AB-example-1
Below are \triangle ABC△ and \triangle DEF△DEFtriangle, D, E, F. We assume that AB-example-2
Below are \triangle ABC△ and \triangle DEF△DEFtriangle, D, E, F. We assume that AB-example-3
Below are \triangle ABC△ and \triangle DEF△DEFtriangle, D, E, F. We assume that AB-example-4
User Saru
by
3.3k points

2 Answers

7 votes

Answer:

A) AB = DE and segments with same length are congruent

User Chrismcg
by
3.5k points
6 votes

Answer:

  • (A) AB = DE and segments with same length are congruent

Explanation:

Justification of step 1 is based on the congruence of segments AB and DE.

Therefore correct choice is the first one:

  • (A) AB = DE and segments with same length are congruent
User Justin Borromeo
by
3.3k points