Question

A solution has a concentration of 40 g.L-1

. We take 20 mL of this solution and add water. The

final volume is 40 mL. What's the new concentration? No calculations but you need to

justify​

Answer 1

Answer: The new concentration is 20 g/L

Step-by-step explanation:

According to the dilution law,

`C_1V_1=C_2V_2`

where,

`C_1` = concentration of stock solution = 40 g/L

`V_1` = volume of stock solution = 20 ml = 0.02 L

`C_2` = concentration of diluted solution= ?

`V_2` = volume of diluted solution= 40 ml = 0.04 L

`40g/L* 0.02L=C_2* 0.04L`

`C_2=20g/L`

Thus new concentration is 20 g/L