Question

a. A student builds a simple circuit with a single resistor with resistance R and measures an electric potential difference ΔV across the resistor. Then, the student replaces the resistor with a new one of resistance 2R and keeps the electric potential difference the same. What is the current (I2) through the new circuit in terms of the original current​

Answer 1

The new current is half the original current.

Explanation:

Ohm's Law:

We use Ohm's law to solve this question. It states that

`\Delta_V = RI`

In which
`\Delta_V` is the voltage difference, R is the resistence, and I is the current.

A student builds a simple circuit with a single resistor with resistance R and measures an electric potential difference ΔV across the resistor.

So

`\Delta_V = RI_(1)`

`I_(2) = (\Delta_V)/(2R) = (1)/(2)((\Delta_V)/(R)) = (1)/(2)(I_1)`

The new current is half the original current.