Question

After a day of use an air compressor is depressurized. The pressure drops from

6.61 to 0.93. If it started at 22.9, what is the new temperature?

Answer 1

41.63K

Step-by-step explanation:

Using gay lussac's equation;

P1/T1 = P2/T2

Where;

P1 = initial pressure

P2 = final pressure

T1 = initial temperature

T2 = final temperature

According to the provided information, P1 = 6.61atm, P2 = 0.93atm, T1 = 22.9°C = 22.9°C + 273 = 295.9K, T2 = ?

Using P1/T1 = P2/T2

6.61/295.9 = 0.93/T2

T2 × 6.61 = 295.9 × 0.93

6.61T2 = 275.187

T2 = 275.187 ÷ 6.61

T2 = 41.63K