Question

I need help solving using the pythagorean theorem.​

Answer 1


`√(11)`

Explanation:

well first you have to plug in a and c in the Pythagorean theorem.

`a^2+b^2=c^2\\(2√(2))^2+b^2 =(√(15))^2`

then squaring the square roots cancels them out sooo it becomes

`4 +b^2=15`

and then isolate b

`b^2 = -4 +15\\\\\\b=√(-4+15) \\b=√(11)`

and there you have it. b is
`√(11)`