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7 votes
Please help me I would really appreciate it

Please help me I would really appreciate it-example-1

2 Answers

11 votes
cos = adjacent / hypotenuse

cos B = 4/5

B = cos^-1 (4/5)

B = 36.869897....

B = 36.87° (nearest hundredth)


Angle B = 36.87°.
User Kaslico
by
5.6k points
4 votes

Answer:


\boxed{\textsf{ The measure of unknown angle is \textbf{ 37}$^(\circ)$.}}

Explanation:

A right angled triangle is given to us with the sides 3 and 4 . We need to find the value of unknown angle that is
\sf \angle ABC .

So , here the measure of hypotenuse is 5 units .


\sf \implies Hypotenuse = 5 \ units .

And the measure of base is 4 units .


\sf\implies Base = 4 \ units .

Let us take the unknown angle be
\theta . That is let us take ,


\sf \implies \angle ABC =\theta

So here we can use the trigonometric ratios of cosine . The cosine can be expressed as a ratio of base and hypotenuse of a right angled triangle . Here ∆ABC . So , cosine is ,


\qquad\boxed{\boxed{\sf cos\theta =(base)/(hypotenuse)}}

Put on the respective values ,


\sf\implies cos\theta =(base)/(hypotenuse)\\\\\sf\implies cos\theta =(4)/(5)\\\\\sf\implies \theta =cos^(-1)\bigg((4)/(5)\bigg) \\\\\sf\implies \boxed{\pink{\sf \theta = 37^(o) . }}

User Sreeragh A R
by
5.1k points