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1.1.50 kg rock falls from the top of a 10.0 m high building and strikes the ground below. What is the force of the ground acting on the rock if it comes to a stop in 0.350 seconds?​

User DKA
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2 Answers

7 votes

Answer:

200×10 idjjcfjcjrjcevdvrfb

User Lsimonetti
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force of the ground acting on the rock if it comes to a stop in 0.350 seconds. V = √2 (9.8) ... Calculate the impulse experienced by the 4.00 kg object represented in the graph below. ... A 200 kg rock is dropped from the top of a 30.0 m high building. ... 200 x 10 seconds, what was the force that the foot applied on the ball?

User Burseaner
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