9514 1404 393
Answer:
70/130 . . . . reduces to 7/13
Step-by-step explanation:
Strategy
The problem statement describes 2 kinds of quiz questions, and different relations regarding the numbers of questions answered correctly. The problem asks for the number of marks Keith had relative to the total number of marks.
This means you need to find Keith's marks and the available marks for each question type (4 numbers).
Because of the way the problem tells you the number of long-answer questions answered, additional computations are required to find the total number of questions Keith answered and the number of short-answer questions Keith answered. (The difference of these is the number of long-answer questions answered.) That's 3 more computations.
You have to keep in mind the purpose of each computation and how it fits in to the final result. This is why we label the intermediate results.
Solution
Short Answer Marks
There were 35 short-answer questions for 2 marks each. That's a total of ...
(35)(2) = 70 . . . . marks for all short-answer questions
Keith got 5/7 of those, so got ...
(5/7)×70 = 50 . . . . Keith's marks for short-answer questions.
__
Long Answer Marks
There were 15 long-answer questions for 4 marks each. That's a total of ...
(15)(4) = 60 . . . . marks for all long-answer questions
The total number of questions on the quiz was 35 +15 = 50. Keith answered 60% of them, so answered ...
0.60×50 = 30 . . . . total number of questions Keith answered
We know Keith answered (5/7)(35) = 25 short-answer questions, so must have answered 30-25 = 5 long-answer questions. His marks for those were ...
(5)(4) = 20 . . . . Keith's marks for long-answer questions
__
Total Marks
Then the total number of marks for all answers on the quiz is ...
short marks + long marks = 70 +60 = 130 . . . available marks
And Keith's overall score was ...
(Keith's short marks + Keith's long marks)/(available marks)
= (50 +20)/130 = 70/130 . . . . Keith's score ratio for the quiz