Question

Prove that
cos 9°+sin 9°/cos9°-sin9° =cot 36°
plzz fasstttt i need to writw this!!!!!!!!!​

Answer 1

Explanation:

LHS = (Cos9° + Sin9°) / (Cos9° - Sin9°)

Divide by Numerator and Denominator by Cos9°

LHS = (1 + Tan9°) / (1 - Tan9°)

= (Tan 45° + Tan 9°) / (1 - Tan 45° * Tan 9°)

= Tan (45°+9°)

= Tan 54°

= Cot 36°

hope it helps :)