Answer:
Explanation:
GIven: Δ JKL ≅ Δ PQR, JK= 6y-21 , PQ = 4X+16, ∠L =(3x-2)
and ∠C = 130°.
Since corresponding parts of two congruent triangles are congruent.
So JK = PQ and ∠C = ∠L
From (ii)
Put this in (i), we get
Hence,
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