217k views
25 votes
Help me please!! I don’t understand

Help me please!! I don’t understand-example-1
User Nagu
by
4.6k points

1 Answer

6 votes

Answer:

3.85 g Zn

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Atomic Structure

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

  • Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

[Given] 3.55 × 10²² atoms Zn

[Solve] grams Zn

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Zn - 65.39 g/mol

Step 3: Convert

  1. [DA] Set up:
    \displaystyle 3.55 \cdot 10^(22) \ atoms \ Zn((1 \ mol \ Zn)/(6.022 \cdot 10^(23) \ atoms \ Zn))((65.39 \ g \ Zn)/(1 \ mol \ Zn))
  2. [DA] Multiply/Divide [Cancel out units]:
    \displaystyle 3.85477 \ g \ Zn

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.85477 g Zn ≈ 3.85 g Zn

User Getzy
by
4.8k points