Question

4NH3(g) + 5O2(g) -> 4NO(g) +6H20(g) If 3.5 L of oxygen gas at STP react with an excess amount of ammonia, how many liters of nitrogen monoxide will be produced

Answer 1

`V_(NO)=2.8L`

Step-by-step explanation:

Hello!

In this case, we consider the given reaction to realize there is a 5:4 mole ratio between oxygen and nitrogen monoxide; thus, we infer that, at STP conditions, such mole ratio is eligible as a volume ratio too; therefore, the produced liters of nitrogen monoxide gas is:

`V_(NO)=3.5LO_2*(4LNO)/(5LO_2) \\\\V_(NO)=2.8L`

Best regards!