Question

3. How many moles of oxygen are needed to react with 4.52 grams of aluminum?

Answer 1

Number moles of oxygen = 0.125

Step-by-step explanation:

Given:

Grams of aluminum = 4.52

Find:

Number moles of oxygen

Computation:

2 Al + 3/2 O2 ⇒ Al2O3

Mole of Al = 4.52 / 27

∵ 2 mole of Al = 3/2 mole of O2

1 mole of Al = (3/2)x(1/2) = 3/4 mole of O2

Number moles of oxygen = (3/4)(4.52/27)

Number moles of oxygen = 0.125