Question

HELP pythagorean identity

Answer 1

Hi!

`\sin^2x+\sin x+\cos^2 x-1=\\\\=\underline{\sin^2x+\cos^2x}+\sin x-1=\\\\=1+\sin x-1=\boxed{\sin x}`

Answer 2

sin x

Explanation:

sin ^2 x + sin x + cos ^ x -1

sin ^2 x + cos ^ x + sin x-1

We know that sin^2 x + cos ^2 x = 1

1 + sin x -1

sin x