Question

Pleasee helpp answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Answer 1

`\boxed {\boxed {\sf d= 13}}`

Explanation:

Distance can be calculated using this formula:

`d= \sqrt {(x_2-x_1)+(y_2-y_1)`

where (x₁, y₁) and (x₂, y₂) are the points. We are given the points (6, -9) and (1, 3). Therefore:

`x_1= 6\\y_1= -9 \\x_2= 1\\y_2=3`

Substitute the values into the formula.

`d= \sqrt {(1-6)^2+(3--9)^2`

Solve inside the parentheses.

• 1-6= -5
• 3--9= 3+9 = 12

`d= \sqrt{(-5)^2 + (12)^2`

Solve the exponents.

• (-5)²= -5*-5 =25
• (12)²= 12 *12= 144

`d= \sqrt { 25+144}`

Add and take the square root.

`d=√(169) \\d= 13`

The distance is 13.