Question

A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation

Answer 1

The right answer is "60.56 atm".

Step-by-step explanation:

As we know,

Vander wall's equation is:

⇒
`(P+(n^2 a)/(v^2) )(v-nb)=nRT`

or,

⇒
`P=(nRT)/((v-nb))-(n^2 a)/(v^2)`

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒
`P=(0.467* 0.0821* 432)/(0.245-0.467* 0.0427)`

`=((0.467)^2* 3.49)/((0.245)^2)`

`=73.61-13.05`

`=60.56 \ atm`