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Payload is released at an elevation of 700 m from a hot air balloon that is rising at a rate of 12 m/s

User Srs
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1 Answer

7 votes

Answer:

Follows are the solution to the given points:

Explanation:

Please find the complete question in the attached file.

Given values:


g= 9.8 \ (m)/(s^2)\\\\u= 12 \ (m)/(s)\\\\h=700 \ m

For point a:


\to V= u-gt


\to V = 12 - 9.8t

For point b:


\to S(t)= ut- (1)/(2)gt^2+h


\to S(t) = 11 t - (1)/(2)9.8 t^2 + 700 \\\\


= 11 t - 4.9t^2 + 700

For point c:


\ Let, \ \ v(t) = 0 \\\\\to 0= 12- 9.8 t\\\\\to 9.8t= 12\\\\\to t= (12)/(9.8)\\\\\to t = 1.22\ sec

Calculating the highest point:


\to s (1.22 ) = 12(1.22) - 4.9(1.22)^2 + 700


= 12(1.22) - 4.9(1.22)^2 + 700 \\\\ = 14.64 - 4.9(1.4884) + 700 \\\\ = 14.64 - 7.29316+ 700 \\\\ = 7.34684+ 700 \\\\ = 707.34684

For point d:


\to s(t) = 0 \to 707.34684 - 4.9t^2=0 \\\\\to 707.34684 = 4.9t^2 \\\\\to t^2=(707.34684)/(4.9) \\\\\to t^2= 144.356498\\\\\to t = 12.01 \ sec\\\\\bold{ \to \text{total time} = 12.01 + 1.22 = 13.23 \ \ sec}

Payload is released at an elevation of 700 m from a hot air balloon that is rising-example-1
User Shubhanshu Mishra
by
3.2k points