Answer:The area of first area is (2t)^2*pi or whatever that variable is, I assume its t because its not clear.
The area to the second circle is t^2*pi
The area together is 80 which means
(4t^2+t^2)pi=80
5t^2pi=80
t^2pi=16
The radius of the smaller circle, t, will be 4/sqrt(pi) or 4sqrt(pi)/pi
So the larger circle has double the radius thus it will be
8/sqrt(pi) or 8sqrt(pi)/pi
This is the value, but if your teacher wants an approximate value just punch this into an calculator :) Hope it helps!
Explanation: