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16 votes
16 votes
P v ~Q => Q
Construct truth table
Please need it ASAP​

User GregPK
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1 Answer

16 votes
16 votes

pq … ¬qp ∨ ¬q … (p ∨ ¬q) ⇒ q

T … T … F … T … T

T … F … T … T … F

F … T … F … F … T

F … F … T … T … F

Start with the first two columns, taking every possible pair of True/False for p and q.

¬q is just the negation of q, so True becomes False and False becomes True.

pq is the logical disjunction, or logical "or". It's True if either p or q is True, and False otherwise. So p ∨ ¬q is True only if either p or ¬q is True.

pq is the logical implication. It's True only when both p and q are True, or when p is False. So (p ∨ ¬q) ⇒ q is True when both p ∨ ¬q and q are True, or when p ∨ ¬q is False.

User Camilo Martin
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