Question

Example 2.13 The acceleration a of a particle in a time t is given by the equation a = 2+ 5t^2. Find the instantaneous velocity after 3s. Solution

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Answer 1

the instantaneous velocity is 51 m/s

Step-by-step explanation:

Given;

acceleration, a = 2 + 5t²

Acceleration is the change in velocity with time.

`a = (dv)/(dt) \\\\a = 2 + 5t^2\\\\The \ acceleration \ (a) \ is \ given \ so \ we \ have \ to \ find \ the \ velocity \ (v)\\\\To \ find \ the \ velocity, \ integrate\ both \ sides \ of \ the \ equation\\\\2 + 5t^2 = (dv)/(dt) \\\\\int\limits^3_0 {(2 + 5t^2)} \, dt = dv\\\\v = [2t + (5t^3)/(3) ]^3_0\\\\v = 2(3) + (5(3)^3)/(3) \\\\v = 6 + 5(3)^2\\\\v = 6 + 45\\\\v = 51 \ m/s`

Therefore, the instantaneous velocity is 51 m/s