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Given: parallelogram ABCD with AB = 2x, CD = 3y + 4, BC = x + 7, and AD = 2y. Find the lengths of the sides of the parallelogram.
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10 votes
10 votes
Given: parallelogram ABCD with AB = 2x, CD = 3y + 4, BC = x + 7, and AD = 2y. Find the

lengths of the sides of the parallelogram.

User Lascarayf
by
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1 Answer

11 votes
11 votes
AB = 58
CD = 58
BC = 36
AD = 36

Explain:

AB = CD
BC = AD
2x = 3y + 4 (1)
x + 7 = 2y (2)
From (1) and (2):
=> x = 29, y = 18
AB = 2x = 2*29 = 58
CD = 3y + 4 = 3*18 + 4 = 58
BC = x + 7 = 29 + 7 = 36
AD = 2*y = 2* 18 = 36
User Nglauber
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