Question

Solve the following system of equations
x^2+2y^2=59
2x^2+y^2=43

Answer 1

Answer: x = (-3,3), y = (-5,5)

Explanation:

Add both of the equations together, for
`3x^(2)+3y^(2) = 102`. Now we can divide both sides by 3, getting
`x^2+y^2=34`. we subtract the first equation from our equation we just got, getting
`y^2=25` y= (5,-5). once we plug that in, we get
`50+x^2 = 59`,
`x^2 = 9` x = (-3,3)