Question

A gas is at a pressure of 97.0 kPa and has a volume of 0.4 L If the pressure increased to 178 kPa, what

will be the new volume? (Temp is constant)
Equation: P1V1 = P2V2
1.36 L
0.73 L
0.22 L
431 L

Answer 1

V₂ ≈ 0.22 L

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Equality Properties

• Multiplication Property of Equality
• Division Property of Equality
• Addition Property of Equality
• Subtraction Property of Equality

Chemistry

Gas Laws

• Pressure
• Boyle's Law: P₁V₁ = P₂V₂

Step-by-step explanation:

Step 1: Define

[Given] P₁ = 97.0 kPa

[Given] V₁ = 0.4 L

[Given] P₂ = 178 kPa

[Solve] V₂

Step 2: Solve for V₂

1. Substitute in variables [Boyle's Law]: (97.0 kPa)(0.4 L) = (178 kPa)V₂
2. [Boyle's Law] Multiply: 38.8 kPa · L = (178 kPa)V₂
3. [Boyle's Law] [Division Property of Equality] Isolate V₂ [Cancel units]: 0.217978 L = V₂
4. [Boyle's Law] [Volume] Rewrite: V₂ = 0.217978 L
5. [Boyle's Law] [Volume] Round: V₂ ≈ 0.22 L