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Please answer this fast and here only​

Please answer this fast and here only​-example-1
User Idrosid
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1 Answer

19 votes
19 votes

Answer:

1) a)
r_(R,I) = 1150\,m, b)
r_(R,II) = 3400\,m, c)
r_(R,III) = 2750\,m.

2) a)
r_(R,I) = 45,2\,km, b)
r_(R, II) = 28,15\,km, c)
r_(R,III) = 51,8\,km.

Step-by-step explanation:

The scale factor is defined by the following expression:


n = (r_(S))/(r_(R)) (1)

Where:


n - Scale factor.


r_(S) - Scale distance, in centimetres.


r_(R) - Real distance, in centimetres.

1) If we know that
n = (1)/(50000),
r_(S,I) = 2,3\,cm,
r_(S,II) = 6,8\,cm and
r_(S,III) = 5,5\,cm, then the actual distances in metres are:


r_(R,I) = (r_(S,I))/(n)


r_(R,I) = (2,3\,cm)/((1)/(50000) )


r_(R,I) = 115000\,cm


r_(R,I) = 1150\,m


r_(R,II) = (r_(S,II))/(n)


r_(R,II) = (6,8\,cm)/((1)/(50000) )


r_(R,II) = 340000\,cm


r_(R,II) = 3400\,m


r_(R, III) = (r_(S, III))/(n)


r_(R,III) = (5,5\,cm)/((1)/(50000) )


r_(R,III) = 275000\,cm


r_(R,III) = 2750\,m

2) If we know that
n = (1)/(50000),
r_(S, I) = 90,4\,cm,
r_(S, II) = 56,3\,cm and
r_(S,III) = 103,6\,cm, then the actual distance in kilometres is:


r_(R,I) = (r_(S,I))/(n)


r_(R,I) = (90,4\,cm)/((1)/(50000) )


r_(R,I) = 4520000\,cm


r_(R,I) = 45,2\,km


r_(R,II) = (r_(S,II))/(n)


r_(R,II) = (56,3\,cm)/((1)/(50000) )


r_(R,II) = 2815000\,cm


r_(R, II) = 28,15\,km


r_(R, III) = (r_(S, III))/(n)


r_(R,III) = (103,6\,cm)/((1)/(50000) )


r_(R,III) = 5180000\,cm


r_(R,III) = 51,8\,km

User Chrismilleruk
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